How do you solve #3x+82=x+2#?

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Answer 1 · 2018-06-25T20:59:35

#x=-40#

Subtract 82

#3x=x-80#

Subtract #x#

#2x=-80#

Divide by 2

#x=-40#

Answer 2 · 2018-06-25T21:12:26

#x=-40#

Let's see if we get our constants on the right and variables on the left. We can start by subtracting #x# from both sides to get

#2x+82=2#

Next, let's get the #82# on the right side by subtracting it from both sides.

#2x=-80#

Lastly, we divide both sides by #2# to get

#x=-40#

Hope this helps!