Question

You drive on the freeway between San Francisco and Sacramento at an average speed of 96 km/h (60 mi/h), and the trip takes 2 h and 10 min. On a rainy day you slow down and drive the same distance at an average speed of 80 km/h (50 mi/h). Question: ?

How much longer does the trip take?

Answer 1

26 minutes more

Explanation:

During the first trip
`V_(av) = 96km*hr^(-1)`

`t=2hr 10min = 13/6 hr`

Total distance travelled(D) is

`rArr D=v_(av)*t rArr D=96*13/6 rArr D=208km`

During the second trip,
`V_(av) = 80 km*hr^(-1)`

`D = 208km`

`t=D/V_(av) rArr t=208/80 rArr t=2.6 hr rArr t=2hr 36min`

This time is 26 minutes more than previous one.