Can u help me with this ?

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Answer 1 · 2018-06-27T12:13:00

Have a look:

You can use the general relationship for a line passing through #(x_0,y_0)# and with slope #m#:

#y-y_0=m(x-x_0)#

Substitute your values and rearrange to get your equation in the form:

#y=mx+c#

Answer 2 · 2018-06-27T12:15:16

See below

You have to memorize that the equation point-slope has the general form

#y-y_0=m(x-x_0)# where m is slope and #(x_0,y_0)# is a line passing point.

In our case

#y-(-3)=-1/4(x-8)#

#y+3=-1/4(x-8)#

we can stop here, but usualy we re-arrange terms in form:

#y=-1/4x+2-3=-1/4x-1# and finally

#y=-1/4x-1#

Answer 3 · 2018-06-27T12:19:50

#color(violet)((y - (-3)) = (-1/4) * (x - 8)# is the required point-slope equation form.

Point-Slope form of equation is #y - y_1 = m * (x - x_1)#

Given : #m = -(1/4), (x_1,y_1) = (8, -3)#

#color(violet)((y - (-3)) = (-1/4) * (x - 8)# is the required point-slope equation form.

#4y + 12 = -x + 8#

#x + 4y + 4 = 0#