Question

How do you evaluate `\ln ( 5^ { 6} \cdot 12) ^ { 4}`?

Answer 1

Remember `log(A·B)=log A+logB` and
`logA^n=nlogA`

Explanation:

Applying log rules

`ln(5^6·12)^4=4ln(5^6·12)=4(ln5^6+ln12)=24ln5+4ln12`