How do solve the following linear system?: # x-3y=-1 , 3y = 15 -6x #?
1 Answer
Jun 27, 2018
Explanation:
#x-3y=-1to(1)#
#3y=15-6xto(2)#
#"from "(1)" we obtain "x=3y-1to(3)#
#"substitute "x=3y-1" in equation "(2)#
#3y=15-6(3y-1)#
#3y=15-18y+6#
#"add "18y" to both sides"#
#21y=21rArry=21/21=1#
#"substitute "y=1" into equation "(3)#
#x=3-1=2#
#"point of intersection "=(2,1)#
graph{(y-1/3x-1/3)(y+2x-5)=0 [-10, 10, -5, 5]}
