How do you graph #2x+y-4=0# by plotting points?
1 Answer
Jul 2, 2018
Explanation:
#"one way is to find the intercepts, that is where the graph"#
#"crosses the x and y axes"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercept"#
#x=0rArry-4=0rArry=4larrcolor(red)"y-intercept"#
#y=0rArr2x-4=0rArrx=2larrcolor(red)"x-intercept"#
#"Plot the points "(0,4)" and "(2,0)#
#"Draw a straight line through them for graph"#
graph{(y+2x-4)((x-0)^2+(y-4)^2-0.04)((x-2)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}