How do you simplify #(2x - 4)/ (x^2 - 3x + 2) times (x^2 - 4x)/4#?

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Answer 1 · 2018-07-02T10:45:30

#(x(x-4))/(2(x-1))#

Lets find the common factors of each term as explained below:

#2x-4# = #2(x-2)#

#x^2-4x# = #x(x-4)#

#x^2-3x+2# = #x^2-1x-2x+2# = #x(x-1)-2(x-1)# = #(x-2)(x-1)#

So now we have:

#(2(x-2))/((x-2)(x-1)) xx (x(x-4))/4#

#(2cancel(x-2))/(cancel(x-2)(x-1)) xx (x(x-4))/4#

#(x(x-4))/(2(x-1))#