Prove The Value Is 0???
#lim# . # x-> oo# .
#√(1+n^2)# -#√(1+n)# #/# #[√(1+n^3)-√(1+n)]#
1 Answer
Jul 2, 2018
When n goes to infinity, you neglect everything except the highest power of n.
The numerator becomes n, and the denominator becomes n^3/2.
The ratio has n^-1/2 as limit, It thus tends to zero as n goes to infinity.
