How do you solve #2x+3-4x-7=11#?

3 Answers
Jul 2, 2018

#x=-15/2#

Explanation:

Rearranging

#2x-4x+3-7=11#
this is

#-2x-4=11#

adding #4# on both sides

#-2x=15#

dividing by #-2#

so

#x=-15/2#

Jul 2, 2018

#x=-15/2#

Explanation:

#"collect terms in "x" on the left side of the equation and"#
#"numeric values on the right side"#

#-2x-4=11#

#"add 4 to both sides"#

#-2x=11+4=15#

#"divide both sides by "-2#

#(cancel(-2) x)/cancel(-2)=15/(-2)rArrx=-15/2#

Jul 2, 2018

#x=-15/2#

Explanation:

We can rearrange this as

#2x-4x+3-7=11#

Now, our like terms are next to each other, which makes it easier to combine. We combine the #x# terms, and the constants to get

#-2x-4=11#

Let's add #4# to both sides to get

#-2x=15#

Dividing both sides by #-2#, we get

#x=-15/2#

Hope this helps!