What is the perimeter of a parallelogram whose diagonals are 6 cm and 8 cm in length?

1 Answer
Jul 3, 2018

It is not possible to find the sides of a parallelogram with the measures of two diagonals only.

Explanation:

Insufficient information. It is not possible to find the sides of a parallelogram with the measures of two diagonals only. It requires at what angle the diagonals intersect to use the pythagoras theorem.

Since Rhombus is a special case of a parallelogram, we can assume ithe shape to be a Rhombus and find the sides.

#"Area of Rhombus "A_R= a^2 = (1/2) d_1 * d_2#

where 'a' is the side of the rhombus and #d_1# and #d_2# the diagonals.

We know #d_1 = 6 cm, d_2 = 8cm#

#:. a^2 = (1/2) * 6 * 8 = 24 " or " a = sqrt24 cm#

#"Perimeter of Rhombus " P_R = 4 * a = 4 * sqrt24 = 19.5959 cm#