What is the limit of #(x^2-1)/(x-1)# as #x# approaches 1?
2 Answers
Jul 3, 2018
I tried this:
Explanation:
I would try manipulating it:
Jul 3, 2018
Explanation:
#lim_(xto1)(x^2-1)/(x-1)#
#=lim_(xto1)(cancel((x-1))(x+1))/cancel((x-1))=1+1=2#