How could i solve this?

Question

the equation #f(x)=x^2 # can be written as #x^3+px^2+q=0#
show that p=-1 and q=-20

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Answer 1 · 2018-07-03T14:34:26

Are you sure you have included all details here? Normally if #f(x)=x^2#, #f(x)!=x^3+px^2+q#, so there is something I don't understand here.