Question

Determine the amount of water required to produce 500 ml of a solution that is 35% of alcohol dissolved in water?

Answer 1

325 mL

Explanation:

`%"(v/v)"="volume of solute"/"volume of solution"*100%`

From the question, alcohol is the solute and water is the solvent . Together, they combine to become solution .

Therefore,
`"volume of solute " = " volume of alcohol"`

`"volume of solution" = "volume of solute" + "volume in solvent" = "volume of alcohol" + "volume of water" = "500 mL"`

Plug in the given values into the percent volume formula to find the volume of alcohol,
`%"(v/v)"="volume of solute"/"volume of solution"*100%`

`35%="volume of alcohol"/"500 mL"*100%`

`"volume of alcohol" = ("35%"*"500 mL")/"100%"="175 mL"`

From the calculated volume of alcohol, we can now find the volume of water,

`"volume of solution" = "volume of alcohol" + "volume of water"`

`"500 mL" = "175 mL" + "volume of water"`

`"volume of water" = "500 mL" - "175 mL" = "325 mL"`