How do you evaluate #int# #dx/(x^2sqrt(x^2 - 9))# with x = 3sec(#theta#)?
Evaluate the integral using the indicated trigonometric substitution. (Use C for the constant of integration.)
#int# #dx/(x^2sqrt(x^2 - 9))# , x = 3sec(#theta# )
Evaluate the integral using the indicated trigonometric substitution. (Use C for the constant of integration.)
1 Answer
Jul 5, 2018
Let
So