How do you solve (x + 2)/2 = (y + 18)/4 and x/3 = (2y + 4)/6?

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Answer 1 · 2018-07-06T17:19:43

#x=12,y=10#

Multiplying the second equation by #3#

#x=3/6*(2y+4)=(2y+4)/2=y+2#

and multiplying the fist equation by #4#

#2(x+2)=y+18#
multiplying out

#2x+4=y+18#
adding #-4#

#2x=y+14#
plugging the equation above (#x=y+2#)

in this equation

#2y+4=y+14#

adding #-4# and #-y#

#y=10#

so #x=12#