How do you graph #y=1/2sqrt(x+2)#, compare to the parent graph, and state the domain and range?
1 Answer
Jul 8, 2018
See answer below
Explanation:
Given:
parent function
horizontal shift 2 left, horizontal stretch by 1/2
Find the domain:
The value under the radical must be
domain:
Find the range:
The range depends on the domain values. Since
range:
graph{1/2 sqrt(x + 2) [-10, 10, -5, 5]}