How do you solve #5/2+1/4x=3-3/8x#?

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Answer 1 · 2018-07-09T08:46:49

#x = 4/5#

As explained below:

Step 1: Shift all variables in one side:

#5/2+(1/4)x# = #3-(3/8)x#

#(1/4)x + (3/8)x# = #3 - 5/2#

Step 2: Simplify both sides:

#(2x + 3x)/8# = #((2 xx 3) - 5)/2#

#(5/8)x# = #(6-5)/2#

#(5/8)x# = #1/2#

#x = 1/2 xx 8/5#

#x = 4/5#

Check the Answer:

#5/2 + (1/4xx 4/5)# = #3 - (3/8 xx 4/5)#

#5/2 + 1/5# = #3 - 3/10#

#(25 + 2)/10# = #(30 - 3)/10#

#27/10# = #27/10# ----> Right!