How do you solve #9(3x – 14) > 5(x – 6)#?

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Answer 1 · 2018-07-09T16:56:31

This is similar to solving equations in algebra. #x > 48/11#

Expand first:
#9(3x-14)>5(x-6)#

#27x-126>5x-30#

#-5x# On both sides.

#22x-126> -30#

#+126# On both sides.

#22x>96#

#/22# Divide by 22.
And...
#x>92/22# which simplifies to #48/11#

Answer 2 · 2018-07-09T17:35:55

#x>48/11#

Let's distribute the #9# on the left side, and the #5# on the right. We now have

#27x-126>5x-30#

We can add #126# to both sides to get

#27x>5x+96#

Next, to get our #x# terms on one side, we can subtract #5x# from both sides:

#22x>96#

Lastly, we can divide both sides by #22# to get

#x>48/11#

Hope this helps!