How do you solve #12- 17( 5- x ) < 4( 5x - 16)#?

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Answer 1 · 2018-07-09T21:38:44

#x> -3#

Let's distribute the #-17# on the left, and the #4# on the right. We now have

#12-85+17x<20x-64#

Let's combine the constants on the left to get

#-73+17x<20x-64#

Next, we can add #73# to both sides to get

#17x<20x+9#

Next, subtract #20x# from both sides to get the #x# terms on the left:

#-3x<9#

Finally, we divide both sides by #-3#. Recall that since we're applying a negative, the sign flips, and we have

#x> -3#

Hope this helps!

Answer 2 · 2018-07-09T21:39:09

#x> -3#

Given inequality

#12-17(5-x)<4(5x-16)#

#12-85+17x<20x-64#

#17x-73<20x-64#

#17x-73+(64-17x)<20x-64+(64-17x)#

#-9<3x#

#3x > -9#

#\frac{3x}{3} >{ -9}/3#

#x> -3#