How do you write #y-6=4/3(x-3)# in standard form?

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Answer 1 · 2018-07-09T22:40:16

#y=4/3x+2#

The given equation of line: #y-6=4/3(x-3)# can be rewritten in slope intercept form as follows

#y-6=4/3x-4/3 \cdot3#

#y=4/3x-4+6#

#y=4/3x+2#

Answer 2 · 2018-07-09T22:44:04

#y=4/3x+2#

We are essentially trying to get this equation into slope-intercept form, so the only thing we want on the left is a #y#.

In our example, we can start by distributing the #4/3# on the right side to get

#y-6=4/3x-4#

Next, let's add #6# to both sides to get

#y=4/3x+2#

Now, our equation is in slope-intercept form, #y=mx+b#.

Hope this helps!