How do you evaluate #3xxsqrt(5) + 2xxsqrt(2)#?

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Answer 1 · 2018-07-10T15:50:03

#9.536#

#3 xx sqrt5 + 2 xx sqrt2#

#3sqrt5 + 2sqrt2#

#sqrt5 = 2.236#

#sqrt2 = 1.414#

Substituting..

#3(2.236) + 2(1.414)#

#6.708 + 2.828#

#9.536#

Answer 2 · 2018-07-10T18:08:05

#3xxsqrt5+2xxsqrt2=color(blue)(3sqrt5+2sqrt2#

Given:

#3xxsqrt5+2xxsqrt2#

Simplify.

#3sqrt5+2sqrt2#

This cannot be simplified further since the radicals are not the same and are prime numbers.