How do you graph #y = 2# by plotting points?
2 Answers
Jul 10, 2018
See a solution process below:
Explanation:
The equation
Therefore, two points on this line are:
We can first plot these points:
graph{((x+2)^2+(y-2)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}
Now, we can draw a straight line through the two points to graph the line:
graph{(y-2+0.000001x)((x+2)^2+(y-2)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}
Jul 11, 2018
See below:
Explanation:
When we have an equation of the form
Our graph, on the
graph{y=0x+2 [-10, 10, -5, 5]}
Hope this helps!