Question

How do you graph `f(x)=(2x-1)/(x+3)` using holes, vertical and horizontal asymptotes, x and y intercepts?

Answer 1

Below

Explanation:

`f(x)=(2x-1)/(x+3)`
`f(x)=(2(x+3)-7)/(x+3)`
`f(x)=2-7/(x+3)`

Therefore, the horizontal asymptote is `y=2` and the vertical asymptote is `x=-3` What asymptotes mean is that the end points of your lines are APPROACHING `y=2` and `x=-3`

Now, to find the intercepts
When `y=0`, `x=1/2`
When `x=0`, `y=-1/3`

After plotting the intercepts and the asymptotes, you should get something like this
graph{(2x-1)/(x+3) [-10, 10, -5, 5]}