Question

A mixture contains 21.7 g NaCl 3.74 g KCI and 9.76 g LiCl. How many moles of NaCl are in the mixture?

Answer 1

`0.371mol`

Explanation:

`n=m/(m_r)`
`m=21.7g`
`m_rNaCl=22.99+35.45=58.44g/(mol)`

`:. n= (21.7cancel(g))/(58.44cancel(g)/(mol))=0.371mol`