How do you simplify # (9-7i)-(10-6i)#?

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Answer 1 · 2018-07-13T20:26:06

#-1 -i#

Given: #(9 - 7i) - (10 - 6i)#

Add/subtract like terms:

#(9 - 7i) - (10 - 6i) = (9 - 10) + (-7i - (-6i))#

#= -1 -7i + 6i = -1 -i#

Answer 2 · 2018-07-13T20:58:37

#-1-i#

#(9-7i)-(10-6i)#

#=9-7i-10+6i#

#=-1-i#

Answer 3 · 2018-07-13T21:28:01

#-1-i#

Let's distribute the negative sign to the second set of parenthesis to get

#9-7i-10+6i#

The good thing is that, for the most part we can treat the imaginary unit like variables. We combine the corresponding parts to get

#-1-i#

Hope this helps!