How to solve this quadratic expression by factoring? n(n +2)

2 Answers
Sonnhard
Jul 16, 2018

#(n+1-1)(n+1+1)#

Explanation:

#n^2+2n+1-1=(n+1)^2-1^2#

remember that

#a^2-b^2=(a+b)(a-b)#
we get

#(n+1-1)(n+1+1)#
so #n=0# or #n=-2#

Jim G.
Jul 16, 2018

#n=-2" or "n=0#

Explanation:

#"the expression is given in factored form"#

#"to solve set equal to zero"#

#n(n+2)=0#

#"equate each factor to zero and solve for n"#

#n+2=0rArrn=-2" or "n=0#

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