How do you convert #2=(8x+y)^2+2y# into polar form?

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Answer 1 · 2018-07-16T12:08:00

The equation is #r^2(8costheta+sintheta)^2+2rsintheta=2#

To convert from rectangular coordinates #(x,y)# to polar coordinates #(r, theta)#, apply the following

#{(x=rcostheta),(y=rsintheta),(x^2+y^2=r^2):}#

The equation

#2=(8x+y)^2+2y#

#(8rcostheta+rsintheta)^2+2rsintheta=2#

#r^2(8costheta+sintheta)^2+2rsintheta=2#

graph{((8x+y)^2+2y-2)=0 [-4.136, 6.96, -2.96, 2.59]}