What is the standard form of #y= (x – 1) (x -5) (x + 3) #?

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Answer 1 · 2018-07-17T05:14:41

#y = x^3 -3x^2 -13x + 15#

Given: #y = (x - 1)(x - 5) (x+3)#

Distribute the first two factors using FOIL :

#y = (x^2 -5x -1x +5)(x + 3)#

Add like terms: #" "y = (x^2 -6x + 5)(x+3)#

FOIL again:

#y = x^3 -6x^2 +5x +3x^2 -18x + 15#

Add like terms: #" "y = x^3 -3x^2 -13x + 15#