Question

What is the gradient of the tangent to the curve y = 4x^3-5x^2+x-7 at the point (2,7)?

Answer 1

Gradient of tangent to the curve at `(2,7)` is `29`

Explanation:

`y= 4 x^3-5 x^2+x-7 ; (2,7)`

`dy/dx = 12 x^2-10 x+1 ;`

At `x=2 , dy/dx = 12* 2^2-10*2+1 =48-20+1=29`

Gradient of tangent to the curve at `(2,7)` is `29` [Ans]