How do you graph #y=x^2 + 1# by plotting points?

1 Answer
Jul 18, 2018

See answer below

Explanation:

Given: #y = x^2 + 1#

This function is a quadratic (square function). When graphed we call this function a parabola.

Graph using point plotting. Since #x# is the independent variable we can select any #x# and calculate the corresponding #y#.

#ul(" "x " "|""-3" "|""-2" "|""-1" "|" "0" "|" "1" "|" "2" "|" "3" "|)#
#" "y" "|" "10" "|" "5" "|" "2" "|" "1" "|" "2" "|" "5" "|" "10" "|#

Graph of #y = x^2 + 1#:

graph{y = x^2 + 1 [-5, 5, -5, 10]}