How do you find the slope of a line with #x#-intercept #3# and #y#-intercept #-4#?

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Answer 1 · 2018-07-19T01:35:36

The slope is #4/3#.

An #x#-intercept is the value of #x# when #y = 0#, so an #x#-intercept of #3# can be written as a coordinate on the graph as #(3, 0)#.

Likewise, an #y#-intercept is the value of #y# when #x = 0#, so an #y#-intercept of #-4# can be written as a coordinate on the graph as #(0, -4)#

Now we have two points, #(3, 0)# and #(0, -4)#.

To find the slope given two points, we use the formula #"rise"/"run"#, or #(y_2-y_1)/(x_2-x_1)#.

Plug in the given points into the formula:
#(-4-0)/(0-3) = -4/-3 = 4/3#

Therefore, the slope is #4/3#.

Hope this helps!