Which term of the geometric sequence 2, 6, 18, ... is 118098?

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Answer 1 · 2018-07-19T03:38:02

11th term

Common ratio #r# is #3#

and first term is #2#

Therefore:
#a_n=2(3)^(n-1)#

#118098= 2(3)^(n-1)#

#59049=3^(n-1)#

#log_3(59049)+1=n#

#10+1=n#

#n=11#