What is the slope and a point on the line of #y = 3 - 2/3(x+4)#?

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Answer 1 · 2018-07-19T03:46:08

slope #= m = -2/3#, point on the line #(-4, 3)#

Given: #y = 3 - 2/3(x +4)#

The point-slope form of a line: #y - y_1 = m( x - x_1)#

Rearrange the given equation to be in point-slope form:

#y - 3 = - 2/3(x - -4)#

slope #= m = -2/3#, point on the line #(-4, 3)#

Answer 2 · 2018-07-19T03:57:10

See below:

We understand point-slope form of a linear equation to be

#y-y_1=m(x-x_1)# with slope #m# and point #(x_1,y _1)#

We can subtract #3# from both sides to easily get this in this form. We now have

#y-3=-2/3(x- -4)#

In this form, we see that our slope is #-2/3# and a point on this line is #(-4,3)#.

Hope this helps!