How do you sketch #(x-1)^2+(y+1)^2=4#?

Question

806 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-21T09:19:42

Please see the explanation below.

The equation of a circle, center #C=(a,b)# and radius #=r# is

#(x-a)^2+(y-b)^2=r^2#

Compare this to your equation

#(x-1)^2+(y+1)^2=4=2^2#

This is the equation of a circle center #=(1,-1)# and radius #=2#

The graph is

graph{(x-1)^2+(y+1)^2=4 [-5.59, 6.894, -5.267, 0.973]}