How do you simplify #(x^(1/pi)/y^(2/pi))^pi#?
3 Answers
Jul 21, 2018
Explanation:
Note that if
#(a^b)^c = a^(bc)#
So (assuming
#(x^(1/pi) / y^(2/pi))^pi = (x^(1/pi))^pi / (y^(2/pi))^pi = (x^(1/pi * pi)) / (y^(2/pi * pi)) = x / y^2#
Jul 21, 2018
Explanation:
Jul 21, 2018