How do you find the vertex of the parabola #y=3x^2+5x+8#?
2 Answers
Explanation:
Given parabola:
The above equation is in standard formula of upward parabola:
Vertex:
Explanation:
#"given a parabola in "color(blue)"standard form"#
#•color(white)(x)y=ax^2+bx+c color(white)(x);a!=0#
#"then the x-coordinate of the vertex is"#
#•color(white)(x)x_(color(red)"vertex")=-b/(2a)#
#y=3x^2+5x+8" is in standard form"#
#"with "a=3,b=5" and "c=8#
#x_("vertex")=-5/6#
#"substitute this value into the equation for y-coordinate"#
#y_("vertex")=3(-5/6)^2+5(-5/6)+8#
#color(white)(xxxx)=25/12-50/12+96/12=71/12#
#color(magenta)"vertex "=(-5/6,71/12)#