What is the slope of the line that goes through #(-4, 6)# and #(4, -3)#?

Question

2837 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-21T16:25:04

#-9/8#

The slope #m# of the straight line passing through the points #(x_1, y_1)\equiv(-4, 6)# & #(x_2, y_2)\equiv(4, -3)#

#m=\frac{y_2-y_1}{x_2-x_1}#

#=\frac{-3-6}{4-(-4)}#

#=\frac{-9}{8}#

#=-9/8#

Answer 2 · 2018-07-21T16:25:14

The slope is #-9/8#

To find the slope, we use the formula #m=(y_2-y_1)/(x_2-x_1)#.

#m=((-3)-(6))/((4)-(-4))#

#m=-9/8#

Answer 3 · 2018-07-21T16:25:43

#-9/8#

We can use the formula

#(Deltay)/(Deltax)#, where the Greek letter Delta (#Delta#) is shorthand for "change in".

We just see how much our #y# changes by, and divide it by how much our #x# changes by.

We go from #y=6# to #y=-3#, which represents a #Deltay# of #-9#.

We go from #x=-4# to #x=4#, which represents a #Deltax# of #8#.

Putting it together, we get

#-9/8#

Hope this helps!