If #z=6z+5# then #z=?#

i dont know how to solve this. Anybody can teach me in a specific way? tq so much.

2 Answers
Jul 22, 2018

#z=-1#

Explanation:

#"collect terms in "z" on one side of the equation and "#
#"numeric values on the other side"#

#"subtract "6z" from both sides"#

#z-6z=5#

#-5z=5#

#"divide both sides by "-5#

#(cancel(-5) z)/cancel(-5)=5/(-5)rArrz=-1#

Jul 22, 2018

#z=-1#

Explanation:

The key is that we want our #z# terms on one side, and the numbers (constants) on the other side.

Let's subtract #6z# from both sides. It is important to do the same thing from both sides to maintain the equality. We get

#-5z=5#

Next, we can do the inverse of multiplication, which is division. Let's divide both sides by #-5# to get

#z=-1#

Hope this helps!