How do you sketch the graph of #y = sec(3x + pi/2)#?
1 Answer
Jul 22, 2018
See explanation and graph.
Explanation:
and
The asymptotes are
The period = period of sin 3x = (2pi)/3
Rewrite
For this form, the Socratic graph is immediate.
graph{(ysin(3x) + 1)(y^2-1)(x^2-1.0966)= 0[-10 10 -5 5]}
Observe