What is the domain of y=-tan^2(x) ?

1 Answer
Jul 23, 2018

#x ne ( 2 k + 1 ) pi/4, k = 0, +-1, +-2, +-3. ...#. See graph.

Explanation:

The asymptotes are x = zeros of the denominator #cos 2x#,

#x = ( 2 k + 1 ) pi / 4, k = 0, +-1, +-2, +-3. ...#
So, #x ne ( 2 k + 1 ) pi / 4, k = 0, +-1, +-2, +-3. ...#

graph{(x-pi/4+0.01y)(y-tan(2x)) =0[-4 4 -2 2]}

One asymptote #x = pi/4# is marked.

The space in between the asympyote and the nearby branch of the

graph #darr# as #abs y uarr# but never becomes 0. So this x is not

in the graph..