Question

How do you simplify `(\frac { - x ^ { 4} y ^ { 4} \cdot - x ^ { - 2} y ^ { 3} } { - x y ^ { - 1} } ) ^ { 4}`?

Answer 1

`x^4y^32`

Explanation:

`((-x^4y^4*-x^(-2)y^3)/(-xy^(-1)))^4`

Numerator:
`-x^4y^4*-x^(-2)y^3`
=`-x^4y^4times-y^3/x^2`
=`x^2y^7`

Denominator:
`-xy^(-1)`
=`-x/y`

Therefore,
`((-x^4y^4*-x^(-2)y^3)/(-xy^(-1)))^4` becomes `((x^2y^7)/(-x/y))^4`
=`((x^2y^7)times-y/x)^4`
=`(-xy^8)^4`
=`x^4y^32`