How do you solve #\frac { - 9} { 5x + 4} < 0#?

1 Answer
Jul 24, 2018

#x in(-4/5,oo)#

Explanation:

#"Calculate the zero of the denominator"#

#5x+4=0rArrx=-4/5#

#"This value splits the domain into 2 intervals"#

#(-oo,-4/5)" and "(-4/5,oo)#

#"select a "color(red)"test point in each interval"#

#x=-1to-9/(-5+4)=9>0#

#x=1to-9/(5+4)=-1<0larrcolor(blue)"satisfies inequality"#

#x in(-4/5,oo)" is the required solution"#
graph{-9/(5x+4) [-10, 10, -5, 5]}