How do you graph #y=2/3sin(pi/3x)#?

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Answer 1 · 2018-07-25T11:58:30

As below.

Standard form of sine function is #y = A sin (Bx - C) + D#

Given #y (2/3) sin ((pi/3)x)#

#A = 2/3, B = pi/3, C = D = 0#

Amplitude #= |A| = 2/3#

Period #= (2pi)/ (pi/3) = 6#

Phase Shift #= -C / |B|= 0#

Vertical Shift #= D = 0#

graph{(2/3) sin ((pi/3)x) [-10, 10, -5, 5]}