How do you multiply #(3z+12)/(8z^3)*(16z^3)/(9z+36)#?

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Answer 1 · 2018-07-25T21:46:26

#2/3#

Given that

#\frac{3z+12}{8z^3}\cdot \frac{16z^3}{9z+36}#

#=\frac{3(z+4)}{8z^3}\cdot \frac{16z^3}{9(z+4)}#

#=(\frac{3\cdot 16}{8\cdot 9})(\frac{z+4}{z+4}) (\frac{z^3}{z^3})#

#=(2/3)(1)(1)#

#=2/3#

Answer 2 · 2018-07-26T10:55:22

#2/3#

#(3z+12)/(8z^3)*(16z^3)/(9z+36)#

=#(3z+12)/(9z+36)*(16z^3)/(8z^3)#

=#(3*(z+4))/(9*(z+4))*2#

=#1/3*2#

=#2/3#