Question

How do you graph `h(x)=ln(x+6)`?

Answer 1

below

Explanation:

The graph `h(x)=In(x+6)` is basically the graph `y=Inx` but shifted to the left by `6` units.

SO, for its intercepts
When `y=0`, `x=-5`
When `x=0`, `y=In6`

Plot the intercepts `(-5,0)` and `(0,In6)` and remember to draw an asymptote at `x=-6` as you cannot log `0` and negative numbers

graph{log(x+6) [-10, 10, -5, 5]}