How do you write the standard equation of the circle the given center that passes with through the given point: center (0, 0); point (3, 4)?
1 Answer
Jul 29, 2018
Explanation:
#"the equation of a circle in standard form is"#
#•color(white)(x)(x-a)^2+(y-b)^2=r^2#
#"where "(a,b)" are the coordinates of the centre and r is"#
#"the radius"#
#"here "(a,b)=(0,0)#
#(x-0)^2+(y-0)^2=r^2#
#x^2+y^2=r^2#
#"the radius is the distance from the centre to the given "#
#"point the circle passes through"#
#r=sqrt(3^2+4^2)=sqrt25=5#
#x^2+y^2=25larrcolor(red)"equation in standard form"#