Domain of a function?

The following intervals contained in the domain of the function
#x-3-:x^2-4# lnx
are?

1 Answer
Jul 29, 2018

The domain for this function is #(0, oo)#. If an interval #I# is contained in the domain of this function, it must be a subset of #(0, oo)# (that is, #I sube (0, oo)#).

Explanation:

The most common things to look at when considering the domain of a function are:

  1. Division by 0

  2. Square root of a negative number

  3. Natural logarithm of non-positive number

Test for the restrictions and combine them to arrive at a final answer.

#x - 3/x^2 - 4lnx#

There is division in #3/x^2#. We must ensure that the denominator is not equal to #0#.

#x^2 ne 0#

#=> x ne 0#

There are no square roots.

There is a natural logarithm in #4lnx#. We must ensure that the input is greater than #0#.

#x > 0#

Combining #x ne 0# and #x > 0#, we simply have #x > 0#.

The domain for this function is therefore #(0, oo)#. If an interval #I# is contained in the domain of this function, it must be a subset of #(0, oo)# (that is, #I sube (0, oo)#).