How do you graph #x+y=3# by plotting points?

2 Answers
Aug 2, 2018

#" "#
Please read the explanation.

Explanation:

#" "#
Given:

#color(red)(x+y=3#

Rewrite this equation as #color(blue)(y = (-x+3))#

We can create a data table for this linear equation and graph:

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Plot some of the points from the table on the graph:

enter image source here

Hope it helps.

Aug 2, 2018

#"see explanation"#

Explanation:

#"one way is to find the intercepts, that is where the graph"#
#"crosses the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArry=3larrcolor(red)"y-intercept"#

#y=0rArrx=3larrcolor(red)"x-intercept"#

#"Plot the points "(0,3)" and "(3,0)#

#"Draw a straight line through them for graph"#
graph{(y+x-3)((x-0)^2+(y-3)^2-0.04)((x-3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}