Question

How do you graph `y=4-sin3(x-pi/3)`?

Answer 1

As below.

Explanation:

Standard form of a sine function is `y = A sin (Bx - C) + D`

Given : `y = - sin (3x - (3pi)/3) + 4`

`A = -1, B = 3, C = pi, D = 4`

`Amplitude = |A| = |-1| = 1`

`"Period " = (2pi) / |B| = (2pi)/3`

`"Phase Shift " = (-C) / B = (-(3pi)/3) / 3 = -pi, color(red)(pi " to the LEFT"`

`"Vertical Shift " = D = 4`

graph{- sin(3x - pi) + 4 [-10, 10, -5, 5]}