Question

What volume is occupied by 500 g of fluorine gas at 5.00oC at a pressure of 735 Torr?

A) 311 L
B) 621 L
C) 5.59 L
D) 11.2 L
E) 295 L

Answer 1

`"Option A..."`

Explanation:

We use the venerable Ideal Gas equation...

`V=(nRT)/P`...

For the pressure term you must simply know that...

`1*atm-=760*mm*Hg`, i.e. one atmosphere will support a column of mercury that is `760*mm*Hg` high...we also MUST KNOW that fluorine, as are ALL the elemental gases with any chemistry is BINUCLEAR, i.e. `F_2`...

And so...

`V=((500*g)/(38.0*g*mol^-1)xx0.0821*(L*atm)/(K*mol)*(273.15+5.00)*K)/((735*mm*Hg)/(760*mm*Hg*atm^-1))`

`-=??*L`